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7x^2=525
We move all terms to the left:
7x^2-(525)=0
a = 7; b = 0; c = -525;
Δ = b2-4ac
Δ = 02-4·7·(-525)
Δ = 14700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14700}=\sqrt{4900*3}=\sqrt{4900}*\sqrt{3}=70\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70\sqrt{3}}{2*7}=\frac{0-70\sqrt{3}}{14} =-\frac{70\sqrt{3}}{14} =-5\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70\sqrt{3}}{2*7}=\frac{0+70\sqrt{3}}{14} =\frac{70\sqrt{3}}{14} =5\sqrt{3} $
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